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You pick a card at random without putting the 1st card back you pick a second card at random what is the probability of picking an 8 and then picking a 5

You Pick A Card At Random Without Putting The 1st Card Back You Pick A Second Card At Random What Is The Probability Of Picking An 8 And Then Picking A 5 class=

Sagot :

Given:

There are four cards numbered

[tex]5,\text{ }6,\text{ }7,\text{ }8[/tex]

Required:

We have to find the probability of picking an 8 and then picking a 5.

Explanation:

The possibility of picking an 8 in the first time is 1 out of the four cards.

Therefore the probability of picking an 8 first is

[tex]\frac{1}{4}[/tex]

Now since you did not put the card back so there are three cards now.

So the possibility of picking a 5 in the second time out of the three cards is 1.

Therefore the probability of picking a 5 in the second time is

[tex]\frac{1}{3}[/tex]

Now we multiply both the probabilities to find the required answer.

Hence the probability of picking an 8 and then a 5 is

[tex]\frac{1}{4}\times\frac{1}{3}=\frac{1}{12}[/tex]

Final answer:

Hence the final answer is

[tex]\frac{1}{12}[/tex]

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