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Prove segment AE is congruent to segment CE?

Sagot :

ABCD is a parallelogram

diagonals AB bisect BD at E

In triangle AED and CEB, DAE = BCE (alternate interior angles)

AD = CB

ADE = CBE (alternate interior angles)

AED CEB (ASA)

Hence, AE = CE and ED = EB

Thus, the diagonals of a parallelogram bisect each other.

Hence, segment AE is congruent to segment CE

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