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Sagot :
So we have to factor this expression:
[tex]-\frac{1}{3}x+\frac{2}{3}[/tex]Using the leading coefficient of the variable term. The variable term is that with x and the leading coefficient is the number multiplying the x, in this case:
[tex]-\frac{1}{3}[/tex]What we are going to do now is take the term that is not the variable term and multiply and divide it by the leading coefficient:
[tex]\begin{gathered} \frac{2}{3}=\frac{2}{3}\cdot\frac{-\frac{1}{3}}{-\frac{1}{3}}=\frac{2}{3}\cdot(-\frac{1}{3})\cdot(-\frac{3}{1})=\frac{2}{3}\cdot(-3)\cdot(-\frac{1}{3}) \\ \frac{2}{3}=(-2)\cdot(-\frac{1}{3}) \end{gathered}[/tex]Then we get:
[tex]-\frac{1}{3}x+\frac{2}{3}=-\frac{1}{3}x+(-2)\cdot(-\frac{1}{3})[/tex]Now that both terms are multiplied by the same number we can factor the expression:
[tex]-\frac{1}{3}x+(-2)\cdot(-\frac{1}{3})=-\frac{1}{3}\cdot(x-2)[/tex]Then the answer is:
[tex]-\frac{1}{3}\cdot(x-2)[/tex]
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