Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Jude says that the volume of a square pyramid with base edges of 12 in and a height of 10 in is equal to the volume of a cylinder with a radius of 6.77 in and a height of 10 in. Jude rounded his answers to the nearest whole numbers. Examine Jude's calculations. Is he correct? Yes, his calculations are correct and the volumes for figures are equal. No, he made a mistake in solving for the volume of the cylinder. Yes, but he made a mistake in solving for the volume of the square pyramid. No, he made a mistake in solving for the volume of both figures.

Sagot :

The volume of the square pyramid

is given by:

[tex]V=\frac{1}{3}Bh[/tex]

where:

[tex]B=s^2[/tex]

where s is the edge of the base.

In this case s = 12.

Therefore,

[tex]B=12^2=144\text{ in}^2[/tex]

h = 10.

[tex]\begin{gathered} V=\frac{1}{3}\times144\times10=480 \\ V=480\text{ in}^3 \end{gathered}[/tex]

Hence, the volume of the square based pyramid is given by:

V = 480 in³

Hence, the volume of the pyramid is correct.

The volume of cylinder is given by:

[tex]\begin{gathered} V=\pi r^2h \\ V=\pi\times6.77^2\times10 \\ V\approx1440\text{ in}^3 \end{gathered}[/tex]

Therefore, Jude use the wrong formula for computing the volume of the cylinder.

Hence, the correct answer is:

No, he made a mistake in solving for the volume of the cylinder.