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On a sunny day, a 15-foot pole casts a 20-foot long shadow, how tall is a person who casts a 8 foot shadow (Draw an image to help you solve the problem). O 10 6 feet O 6 feet O 375 feet O B feet None of the above

Sagot :

The image can be drawn as,

The height of the person can be determined as,

[tex]\begin{gathered} \tan C=\frac{AB}{CB}=\frac{DE}{CE} \\ \frac{AB}{CB}=\frac{DE}{CE} \\ \frac{15}{20}=\frac{DE}{8} \\ DE=\frac{15\times8}{20} \\ DE=6\text{ ft} \end{gathered}[/tex]

Thus, the required height of the man is 6 ft.

View image ZeviP487987