Answered

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Consider the equation -3x+4y=-12 A line parallel to the above line would have a slope of ()/(frac{3}{4}) what would A line perpendicular to the above line have a slope of?

Sagot :

[tex]m=-\frac{4}{3}[/tex]

1) Perpendicular lines have reciprocal and opposite slopes. But to properly check it, we need to rewrite the Standard form to the Slope-intercept

So let's rewrite it:

[tex]\begin{gathered} -3x+4y=-12 \\ 4y=-12+3x \\ y=-\frac{12}{4}+\frac{3}{4}x \\ y=\frac{3}{4}x-3 \end{gathered}[/tex]

2) Now, we can clearly see the slope. So now, we can tell that a perpendicular line would be reciprocal and opposite to the slope so we can tell that a perpendicular line will be:

[tex]m=-\frac{4}{3}[/tex]

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