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I have worked through this question but am still confused on how to figure this out

I Have Worked Through This Question But Am Still Confused On How To Figure This Out class=

Sagot :

We are given two solutions of C12H22O11, where solution 1 is 20% and solution 2 is 60%.

We want to know how much of each solution we need to get 38% in 50 mL of C12H22O11.

We can use the following equation:

C1V1 = C2V2

For a 20% concentration:

V1 = C2V2/C1

= (38% x 50mL)/20%

= 95mL

For a 60% concentration:

V1 = C2V2/C1

= (38% x 50mL)/60%

= 31.6mL

So to get a 50mL of 38%, you can use the 20% solution provided, you will need to use 95 mL of 20% concentration to get 38% final concentration. And if you use the 60% concentration solution provided, you will need to use 31.6mL.

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