Answered

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y varies directly as x. y =84 when x=6. Find y when x=12y= ?

Sagot :

If y varies directly as x, we have that

[tex]y\propto x[/tex]

Then

[tex]y=kx(where\text{ k is a constant\rparen}[/tex][tex]\begin{gathered} When\text{ y=84 , x= 6} \\ y=kx \\ 84=6k \\ k=\frac{84}{6}=14 \end{gathered}[/tex]

The relationship between x and y is given as

[tex]\begin{gathered} y=kx \\ y=14x \end{gathered}[/tex]

Therefore when x= 12, y=?

[tex]\begin{gathered} y=14x \\ y=14\times12=168 \end{gathered}[/tex]

Hence, the value of y when x = 12 is 168

Final answer: y = 168

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