Answered

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Find the area of triangle ABC.A = 37.2°, b = 10.1 in., c = 6.2 in.A. 19 in²B. 20 in²C. 17 in²D. 18 in²

Sagot :

Given:

A = 37.2°

b = 10.1 in

c = 6.2 in

Let's find the area of the traingle.

To find the area, apply the formula below:

[tex]\text{Area}=\frac{1}{2}\ast b\ast c\ast\sin A[/tex]

Hence, we have:

[tex]Area=\frac{1}{2}\ast10.1\ast6.2\ast\sin 37.2[/tex]

Solving further:

[tex]\begin{gathered} \text{Area}=\frac{1}{2}\ast10.1\ast6.2\ast0.605 \\ \\ \text{Area}=18.9\text{ }\approx19in^2 \end{gathered}[/tex]

Therefore, the area of triangle ABC is 19 square inches

ANSWER:

A. 19 in²

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