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Determine the intercepts of the line y=51 - 13 y-intercept: ( x-intercept: ( )

Sagot :

[tex]\begin{gathered} y-\text{intercept}(0,-13) \\ x-\text{intercept}(\frac{13}{5},0) \end{gathered}[/tex]

Explanation

[tex]y=5x-13[/tex]

the y-intercept is the point where the line intersects the y-axis, it is when x=0

and

the x-intercept is the point where the line intersects the x-axis,this is when y=0

so

Step 1

y-intercept

let x=0 and replace

[tex]\begin{gathered} y=5x-13 \\ y=5\cdot0-13 \\ y=0-13 \\ y=-13 \end{gathered}[/tex]

so, the ordered pair is ( 0,-13)

Step 2

x-intercept

let y=0 and solve for x

[tex]\begin{gathered} y=5x-13 \\ 0=5x-13 \\ \text{add 13 in both sides} \\ 0+13=5x-13+13 \\ 13=5x \\ \text{divide both sides by 5} \\ \frac{13}{5}=\frac{5x}{5} \\ \frac{13}{5}=x \end{gathered}[/tex]

hence, the ordered pair is (13/5, 0)

I hope this helps you

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