The general equation of a vertex of a parabola is given by
[tex]\begin{gathered} y=a(x-h)^2+k \\ \text{where} \\ \text{The coordianates of the vertex are} \\ (h,k) \end{gathered}[/tex]
If we compare the general equation with that given in question 2
[tex]y=2(x-3)^2+6[/tex]
We can infer that
[tex]\begin{gathered} -h=-3 \\ \text{Hence} \\ h=3 \\ \text{Also} \\ k=6 \end{gathered}[/tex]
Thus, the vertex is
[tex](h,k)=(3,6)[/tex]
To determine if it is maxima or minima, we will use the graph plot
We can observe that we have a minimum value.
Usually, we can determine this also from the value of a.
If a is negative, we have a maxima
If a is positive, we have a minimum
The value of a =2 (Positive)
Hence, we have a minimum
