Answered

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If a ball is dropped from a bridge that is 36.4 meters high, how long will it take until the ball hits the ground below the bridge?

Sagot :

2.72 sec

Explanation

Step 1

to solve this we need to use the formula

[tex]h=v_0t+\frac{1}{2}gt^2[/tex]

let

[tex]\begin{gathered} v_0=0 \\ h=36.4\text{ m} \\ g=9.8\text{ }\frac{\text{m}}{s^2} \\ t=\text{ unknown= t} \end{gathered}[/tex]

replace

[tex]\begin{gathered} h=v_0t+\frac{1}{2}gt^2 \\ 36.4=0\cdot t+\frac{1}{2}(9.8\text{ }\frac{m}{s^2})t^2 \\ 36.4=+(4.9\frac{m}{s^2})t^2 \\ \text{divide both sides by 4.9} \\ \frac{36.4}{4.9}=t^2 \\ t=\sqrt[]{7.42} \\ t=2.72 \end{gathered}[/tex]

therefore, the answer is

2.72 sec

I hope this helps you

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