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Sagot :
We have to write the net ionic equation for the reaction between HCl and NaHCO₃.
The molecular equation will show us the products of this equation.
Molecular equation:
HCl (aq) + NaHCO₃ (aq) ------> NaCl (aq) + CO₂ (g) + H₂O (l)
Now we can split this compounds into their ions to get the total ionic equation:
Total ionic equation:
H+ (aq) + Cl- (aq) + Na+ (aq) + HCO3- (aq) ----> Na+ (aq) + Cl- (aq) + CO₂ (g) + H₂O (l)
And finally we can identify the spectator ions. The ones that we have on both sides, they are Na+ and Cl-. We can cancel them out.
Net ionic equation:
H+ (aq) + HCO3- (aq) ----> CO₂ (g) + H₂O (l)
Answer: H+ (aq) + HCO3- (aq) ----> CO₂ (g) + H₂O (l)
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