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Question 12(Multiple Choice Worth 1 points)(07.04 LC)Factor completely 36x² - 49.(3x + 7)(12x-7)(3x-7)(12x+7)(6x-7)(6x-7)(6x + 7)(6x-7)

Sagot :

The factor the binomial

[tex]a^2-b^2[/tex]

Find the square root of a and the square root of b, then put them as the product of the sum and difference of these square roots

[tex]\begin{gathered} \sqrt{a^2}=a \\ \sqrt{b^2}=b \\ a^2-b^2=(a+b)(a-b) \end{gathered}[/tex]

We will use this rule to factor in the given expression

[tex]36x^2-49[/tex]

Find the square root for each term

[tex]\begin{gathered} \sqrt{36x^2}=6x \\ \sqrt{49}=7 \end{gathered}[/tex]

Write the two factors

[tex]36x^2-49=(6x+7)(6x-7)[/tex]

The answer is the last choice (6x + 7)(6x - 7)