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Sagot :
Since the sides of the rectangle are in ratio 5: 7
Insert x in the 2 terms of the ratio and find its perimeter using them
[tex]\begin{gathered} L\colon W=5x\colon7x \\ P=2(L+W) \\ P=2(5x+7x) \\ P=2(12x) \\ P=24x \end{gathered}[/tex]Equate 24x by the given perimeter 72 to find the value of x
[tex]24x=72[/tex]Divide both sides by 24
[tex]\begin{gathered} \frac{24x}{24}=\frac{72}{24} \\ x=3 \end{gathered}[/tex]Then the sides of the rectangle are
[tex]\begin{gathered} L=5(3)=15 \\ W=7(3)=21 \end{gathered}[/tex]Since the rule of the area of the rectangle is A = L x W, then
[tex]\begin{gathered} A=15\times21 \\ A=315 \end{gathered}[/tex]The area of the rectangle is 315 square units
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