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Graph the parabola.y=1/4x^2-1Plot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. Then click on the graph-a-function button

Sagot :

This is basic parabola of the form:

[tex]y=ax^2-b[/tex]

So, this one is shifted 1 units down.

The vertex is at (0, -1).

To take 2 points to the left of vertex, we find coordinates for x = -2 and x = -4.

To take 2 points to the right of vertex, we find coordinates for x = 2 and x = 4.

Let's find it:

[tex]\begin{gathered} \text{When x = -2,} \\ y=\frac{1}{4}x^2-1 \\ y=\frac{1}{4}(-2)^2^{}-1 \\ y=0 \\ When\text{ x = -4,} \\ y=\frac{1}{4}x^2-1 \\ y=\frac{1}{4}(-4)^2-1 \\ y=3 \\ \text{When x = 2,} \\ y=\frac{1}{4}x^2-1 \\ y=\frac{1}{4}(2)^2-1 \\ y=0 \\ \text{When x= 4,} \\ y=\frac{1}{4}x^2-1 \\ y=\frac{1}{4}(4)^2-1 \\ y=3 \end{gathered}[/tex]

So, the 4 coordinates are:

(-2,0), (-4,3), (2,0), (4,3)

The graph:

View image KamdinH510777
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