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In circle C with mZBCD = 66 and BC = 15 units find area of sector BCD. Round to the nearest hundredth. с B D

Sagot :

ANSWER:

The area of sector BCD is 129.53 square units

STEP-BY-STEP EXPLANATION:

The first thing is to calculate the area of the circle completely. That area would be for 360 °, therefore by means of a proportion we can calculate the area for the BDC sector.

The area of circle is:

[tex]\begin{gathered} A=\pi\cdot r^2 \\ \text{replacing} \\ A=3.14\cdot15^2 \\ A=706.5 \end{gathered}[/tex]

Now, we calculate the area of the BDC sector by means of the following portion

[tex]\frac{706.5}{360}=\frac{x}{66}[/tex]

Solving for x:

[tex]\begin{gathered} x=66\cdot\frac{706.5}{360} \\ x=129.525\cong129.53 \end{gathered}[/tex]