Answered

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Solve the system of equations: 2x + 3y = 8 and 3x - 3y = 12.

Solve The System Of Equations 2x 3y 8 And 3x 3y 12 class=

Sagot :

[tex](4,0)[/tex]

1) In this problem, let's solve this given system of equations by the method of Elimination.

We can start by adding both equations simultaneously:

[tex]\begin{gathered} 2x+3y=8 \\ 3x-3y=12 \\ --------- \\ 5x=20 \\ \\ \frac{5x}{5}=\frac{20}{5} \\ \\ x=4 \end{gathered}[/tex]

Now, that we know the quantity of x, let's plug it into any of those equations. Most of the time, we opt to plug it into the simpler equation.

[tex]\begin{gathered} 2x+3y=8 \\ 2(4)+3y=8 \\ 8+3y=8 \\ -8+8+3y=8-8 \\ 3y=0 \\ \frac{3y}{3}=\frac{0}{3} \\ \\ y=0 \end{gathered}[/tex]

2) Thus, the answer is (4,0)

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