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Sagot :
Given the polynomial has zeros = -3, 3, 5
so, the factors are:
[tex](x+3),(x-3),(x-5)[/tex]Multiplying the factors to find the equation of the polynomial:
So,
[tex]\begin{gathered} y=(x-3)(x+3)(x-5) \\ y=(x^2-9)(x-5) \\ y=x^2(x-5)-9(x-5) \\ y=x^3-5x^2-9x+45 \end{gathered}[/tex]But the coefficient of x^2 is -10.
So, Multiply all the coefficients by 2
So, the answer will be:
The polynomial is:
[tex]2x^3-10x^2-18x+90[/tex]
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