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Sagot :
[tex]\begin{gathered} \sin ce\text{ the diameter of marble is given then the marble is a sphere} \\ \text{from the question;} \\ \text{diameter = 62mm, this implies } \\ \text{radius = }\frac{62}{2}\text{ = 31mm} \\ \text{applying the formula for volume of sphere} \\ \text{volume of sphere = }\frac{4}{3}\pi r^3 \\ \text{volume of sphere = }\frac{4}{3}\text{ }\times\text{ }\frac{22}{7}\times31^3 \\ \text{volume of sphere = 124838.48}mm^3 \\ \text{volume of sphere }\cong124,838mm^3\text{ to the nearest cubed millimeter} \\ \\ \text{hence volume of marble = 124, 838mm}^3 \end{gathered}[/tex][tex]\begin{gathered} \sin ce\text{ the marble cracked into equal pieces then} \\ \\ \text{volume of one piece = }\frac{\text{volume of sphere}}{2} \\ \text{volume of one piece = }\frac{124,838}{2}mm^3 \\ \text{volume of one piece = 62,419mm}^3\text{ to the nearest cubed millimeter} \end{gathered}[/tex]
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