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Instructions: Given the recursive rule, match it to the explicit form.

Instructions Given The Recursive Rule Match It To The Explicit Form class=

Sagot :

Explanation:

If we have a recursive expression with the form

[tex]a_n=a_{n-1}\cdot c[/tex]

Then, the explicit formula is

[tex]a_n=a_1\cdot c^{n-1}[/tex]

Therefore, for each option, we get:

[tex]\begin{gathered} a_n=a_{n-1}\cdot2\text{ with a}_1=1 \\ \text{ Then} \\ a_n=1\cdot2^{n-1}=2^{n-1} \end{gathered}[/tex][tex]\begin{gathered} a_n=a_{n-1}\cdot-2\text{ with a}_1=2 \\ \text{ Then} \\ a_n=2\cdot(-3)^{n-1} \end{gathered}[/tex][tex]\begin{gathered} a_n=a_{n-1}\cdot4\text{ with a}_1=-1 \\ \text{ Then} \\ a_n=-1\cdot4^{n-1}=-4^{n-1} \end{gathered}[/tex][tex]\begin{gathered} a_n=a_{n-1}\cdot2\text{ with a}_1=-3 \\ \text{ Then} \\ a_n=-3\cdot2^{n-1} \end{gathered}[/tex]

Answer:

Therefore, the answer is:

View image SetonR362069
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