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graph a line that passes through (-4,1) and has a slope of -3

Sagot :

We are given a point with coordinates;

[tex]\begin{gathered} (x,y)=(-4,1) \\ m=-3 \end{gathered}[/tex]

We begin by expressing the line in slope-intercept form as follows;

[tex]\begin{gathered} y=mx+b \\ \text{Where,} \\ (x,y)=(-4,1) \\ m=-3,\text{ we now have} \\ 1=-3(-4)+b \\ 1=12+b \\ \text{Subtract 12 from both sides;} \\ 1-12=12-12+b \\ b=-11 \\ The\text{ equation now becomes;} \\ y=mx+b \\ y=-3x+(-11) \\ y=-3x-11 \end{gathered}[/tex]

The graph would now be a shown below;

View image SaliseS308985
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