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Sagot :
It is given that,
The amount she invested in Fund A was $7000 less than the amount she invested in Fund B.
So, A=B-7000
And it is given that, Fund A returned a 7% profit and Fund B returned a 3% profit.
The total profit from the two funds together was $1610.
It can be written as,
7% of A +3% of B=1610
Substitute A=B-7000, we get
7% of (B-7000) +3% of B=1610
On solving we get,
[tex]\begin{gathered} \frac{7}{100}(B-7000)+\frac{3}{100}B=1610 \\ \frac{7}{100}B-490+\frac{3}{100}B=1610 \\ \frac{10}{100}B-490=1610 \\ \frac{1}{10}B=1610+490 \\ \frac{1}{10}B=2100 \\ B=21000 \end{gathered}[/tex]Hence, the investment in fund B is $21,000.
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