Answered

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3. Brust is riding his bicycle north away from an intersection at a rate of 15 miles per hour. Sully is driving his car towards the intersection from the west at a rate of 30 miles per hour. If Brust is 0.4 miles from the intersection, and Sully is 1 mile from the intersection, at what rate is the distance between the two of them increasing or decreasing?

Sagot :

The graph shows the situation of Brust and Sully. The distance between them is d

If x is the distance from Sully to the intersection and y is the distance from Brust to the intersection, the distance d is

[tex]d=\sqrt[]{x^2+y^2}[/tex]

The rate of change of d in time is computed by taking the derivative:

[tex]d^{\prime}=\frac{xx^{\prime}+yy^{\prime}\text{ }}{\sqrt[]{x^2+y^2}}[/tex]

We have the following parameters:

x=1, y=0.4, x'=-30, y'=15

Substituting:

[tex]d^{\prime}=\frac{(1)(-30)+(0.4)(15)\text{ }}{\sqrt[]{1^2+0.4^2}}[/tex]

d' = -22.3 miles per hour

Since d' is negative, the distance is decreasing

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