Answered

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what is the area of a workshop that is 4 yard wide and 5 2/3 yard long

Sagot :

Solution

For this case we can start doing this:

[tex]5\frac{2}{3}=\frac{5\cdot3+2}{3}=\frac{17}{3}[/tex]

and then we can find the are on this way:

[tex]A=\frac{17}{3}yd\cdot4yd=\frac{68}{3}yd^2[/tex]

And we can rewrite this expression as:

[tex]22\frac{2}{3}[/tex]

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