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A wheelchair ramp needs to be pitched at gº. If the ramp is used to access an 18-inch step to a door, what will be the length of the ramp to the nearest inch? Sin 80 = 0.139 Cos 80 =0.990 Tan 8° 0.1405 O A. 3 inches o B. 96 inches O C. 44 inches D. 129 inches

A Wheelchair Ramp Needs To Be Pitched At Gº If The Ramp Is Used To Access An 18inch Step To A Door What Will Be The Length Of The Ramp To The Nearest Inch Sin 8 class=

Sagot :

it is given that,

the given ramp is a right angle ramp withe the angle 8 degrees,

it is given that

the ramp is used to access an 18-inch step to a door

so, the perpendicular of the ramp is P = 18 in

the length of the ramp is = hypotenuse,

[tex]\sin \theta=\frac{\text{perpendicular}}{\text{hypotenuse}}[/tex][tex]\begin{gathered} \sin 8=\frac{18}{\text{hypotenuse}} \\ \text{hypotenuse = }\frac{18}{0.139} \\ \text{hypotenuse = 129.49} \end{gathered}[/tex]

so, the length of the ramp is approx 129 in.

thus, the correct answer is option D

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