Answered

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It says," use the rectangle. Round to the nearest tenth."

It Says Use The Rectangle Round To The Nearest Tenth class=

Sagot :

To find the perimeter and the area of the rectangle you must have its length and width

So we will find AB as width and BC as a length

The rule of the distance between two points is

[tex]d=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]

A = (2, 6) and B = (4, 3)

x1 = 2 and x2 = 4

y1 = 6 and y2 = 3

Substitute them in the rule to find AB

[tex]AB=\sqrt[]{(4-2)^2+(3-6)^2}=\sqrt[]{4+9}=\sqrt[]{13}[/tex]

B = (4, 3) and C = (10, 6)

x1 = 4 and x2 = 10

y1 = 3 and y2 = 6

[tex]BC=\sqrt[]{(10-4)^2+(6-3)^2}=\sqrt[]{36+9}=\sqrt[]{45}=3\sqrt[]{5}[/tex]

The perimeter of the rectangle

[tex]P=2\lbrack\sqrt[]{13}+3\sqrt[]{5}\rbrack=20.6[/tex]

The area of the rectangle

[tex]A=\sqrt[]{13}\times3\sqrt[]{5}=24.2[/tex]

The perimeter = 20.6 units

The area = 24.2 square units

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