Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Given the following equation provided in the exercise:
[tex]x+6y=-36[/tex]You can solve for the variable "y" by following the steps shown below:
1. You must apply a property called "Subtraction property of equality". This states that:
[tex]\text{If }A=B,\text{ then }A-C=B-C[/tex]So you must subtract "x" from both sides of the equation:
[tex]\begin{gathered} x+6y-(x)=-36-(x) \\ 6y=-36-x \end{gathered}[/tex]2. Finally, you must apply the "Division property of equality". This states that:
[tex]\text{If }A=B,\text{ then }\frac{A}{C}=\frac{B}{C}[/tex]Then, dividing both sides of the equation by 6, you get the equation solved for "y" is:
[tex]\begin{gathered} \frac{6y}{6}=-\frac{36}{6}-\frac{x}{6} \\ \\ y=-\frac{x}{6}-6 \end{gathered}[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
