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Sagot :
The planet has an approximate mass of: 5.2815*10^10 metric tones
To solve this problem the formulas and the procedures that we have to use are:
- c = 2 * π * r
- v= (4 *π * r³) / 3
- d = m/v
Where:
- c = circumference of a sphere
- π = mathematical constant
- r = radius
- v= volume
- d= density
- m= mass
Information about the problem:
- c = 23500 km
- d = 2.41 g/ml
- π = 3.1416
- 1 metric tone = 1000 kg
- r=?
- v = ?
- m =?
Applying the circumference of a sphere formula and clearing the radius we get:
c = 2 * π * r
r = 23500 km / 2 * 3.1416
r = 3740.132 km
Applying the volume of the sphere formula we get:
v= (4 *π * r³) / 3
v= (4 *3.1416 * (3740.132 km)³) / 3
v = 2,1915 *10^11 km³
By converting the volume units from (km³) to (ml) we have:
v = 2,1915 *10^11 km³ * 1*10^5 ml/1 km³
v = 2.1915*10^16 ml
Applying the density formula and clearing the mass we get:
d = m/v
m = d * v
m = 2.41 g/ml * 2.1915*10^16 ml
m = 5.2815*10^16 g
By converting the mass units from (g) to (metric tone) we have:
m = 5.2815*10^16 g * 1 kg/1000 g * 1 metric tone/1000 kg
m = 5.2815*10^10 metric tones
What is density?
It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
Learn more about density in: brainly.com/question/1354972
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