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Sagot :
The length and width of the given rectangle is 10.77 and 5.385 respectively.
According to the question statement, The length of a rectangle is twice the width and the area of the rectangle is 58 square units.
We are supposed to find the length and width of the rectangle.
Before solving this we need to know that the area of the rectangle is the product of its length and width,
Let's assume the length be "l" and width be "w"
Therefore Area = l*w
Now as length is twice the width so [tex]l=2w[/tex]
Area = [tex]58 square units[/tex]
Therefore [tex]l*w=58\\[/tex]
but [tex]l=2w[/tex]
[tex]2w*w = 58\\2w^{2}=58\\w^{2} = \frac{58}{2} \\w^{2}= 29[/tex]
[tex]w=\sqrt{29} \\w=5.385[/tex]
as [tex]l=2w[/tex]
[tex]l=2*5.385\\l=10.77[/tex]
Hence length l = 10.77 unit and width w = 5.385 unit
- Area: Area is defined as the total space taken up by a 2D or a 3D surface or an object.
To learn more about surface areas, click on the link given below.
https://brainly.com/question/92701
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