At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Percent of gold and copper are 88.2 and 11.8
Red gold is a gold-copper alloy used to make jewelry .
Let the mass of gold be m1
Let the mass of copper be m2
We are given that m1+m2 =8.97 g
We know that volume is the ratio of mass to density
Thus
m1/d1 + m2/d2 = 0.528 cm3
where d1 and d2 is the density of gold and copper
m1/19.3 + m2/8.96 = 0.528
8.96m1 +19.3 m2 = 0.528 x 19.3 x 8.96 = 91.305
putting m1 = 8.97 - m2
8.96 ( 8.97 - m2 ) + 19.3 m2 = 91.305
80.3712 - 8.96m2 + 19.3 m2 =91.305
10.34 m2 = 91.305-80.3712
m2 = 10.9338 /10.34
=1.0537gm
m1=8.97-1.0537
=7.91gm
Therefore, percent of gold = 7.91/8.97 x 100 =88.20%
percent of copper = 100-88.2=11.8%
Therefore, percent of gold and copper are 88.2 and 11.8
For further reference:
https://brainly.com/question/18712497?referrer=searchResults
#SPJ9
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.