Answered

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An infant acetaminophen suspension contains 80.0mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight. (1.000 lb. is equivalent to 453.59 g; this is a measured equality.)

How many mL of this suspension should be given to an infant weighing 17 lb ? (Assume two significant figures.)
Express your answer using two significant figures.

Sagot :

Oseni

The amount, in mL, of the suspension that should be given to an infant weighing 17 lb will be 1.16 mL

Dimensional analysis

0.8 mL of the liquid contains 80.0 mg of the drug.

The recommended dose is 15 mg per kg of body weight

The infant to be given the drug weighs 17 lb.

First, let's convert the weight of the infant to kg.

1 lb = 453.59 g

17 lb =       453.59 x 17/1

                   = 7711.03 g

1000 g = 1 kg

7711.03 g = 7711.03 x 1/1000

               = 7.711 kg

So, the baby's weight is 7.711 kg.

The drug dose for the baby can thus be calculated as:

15 mg x 7.711 = 115.67 mg

But 0.8 mL of the drug contains only 80.0 mg. How many mL will contain 115.67 mg?

                   0.8 x 115.67/ 80.0 = 1.16 mL

More on dimensional analysis can be found here: https://brainly.com/question/13078117

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