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Calculate the ph of a solution prepared by dilution 3.0 ml of 2.5 m hcl to a final volume of 100 ml with h2o.

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The pH of the solution after dilution is 1.125.

HCl is hydrochloric acid. It is known by the name muriatic acid. It is among the strong acids. It has a pungent smell and is colorless. It has a molar mass of 36.4 g/mol. It's a common reagent used in pharmaceutical industries. It is also used in other industries such as textile, rubber, and metal.

The volume of HCl added to the solution = 3.0 ml

The molar concentration of HCl = 2.5 M

Let the molar concentration of the solution after dilution is x.

The volume of the diluted solution = 100 ml.

The molar concentration of the solution after dilution is,

[tex]M _{1} V _{2} = M_{2} V _{2} [/tex]

[tex]M_{2} = \frac{ M _{1} V _{2}}{V _{2} }[/tex]

[tex]M_{2} = \frac{2.5 \times 3}{100} [/tex]

[tex] = 0.075 \: M[/tex]

Thus, the molar concentration of the solution after dilution is 0.075 M.

The pH of the solution after the dilution is,

[tex][HCl] = [H ^{ + } ] = 0.075 \: M[/tex]

[tex]pH = - log [H ^{ + } ] [/tex]

[tex]pH = - log(0.075)[/tex]

[tex]pH = 1.125[/tex]

Therefore, the pH of the solution after dilution is 1.125.

To know more about hydrochloric acid, refer to the below link:

https://brainly.com/question/3637432

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