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Sagot :
The percentage decomposed in the first order reaction is 69.8%.
What percentage of the compound has decomposed after 7.1 seconds?
Given: rate constant, k = 0.00702 sec -1
time, t = 7.1 s
Since the reaction is first order, we calculate using the formula below:
[A] = [A]₀ [tex]$e^{(-kt)[/tex]
Where; [A] is the final concentration
[A]₀ is the initial concentration
Finding the ratio of final and initial concentration
[A]/[A]₀ =[tex]$ e^{(-kt)[/tex]
Substituting the values:
[A]/[A]₀ = [tex]e^{(-0.00702 * 7.1)[/tex]
[A]/[A]₀ = [tex]e^{(-0.0498)[/tex]
[A]/[A]₀ = 0.9514
Percentage decomposed = [A]/[A]₀ [tex]*[/tex] 100%
Percentage decomposed = 0.9514 [tex]*[/tex] 100%
Percentage decomposed = 95.1 %
Therefore, the percentage decomposed in the first-order reaction is 95.1 %.
To learn more about percentage decomposition refer to: brainly.com/question/1563644
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