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The difference of two natural number is 2. The sum of their squares is 100.Find the numbers.

Sagot :

varshamittal029

The required two numbers are 6 and 8.

Let us denote the required numbers by c and d.

Given that the difference between two natural numbers is 2.

If we assume d > c, then d – c = 2

⇒ d = 2 + c → equation 1.

Also given that the sum of their squares is 100.

⇒ c² + d² = 100

⇒ c² + (2 + c)² = 100 (using the value of d from equation 1)

⇒ 2c² + 4c + 4 = 100

⇒ 2c² + 4c = 96

⇒ 2c(c+2) = 96

⇒ c(c+2) = 48

Using the factorization for 48, we get 6 × 8 = 48

⇒ c = 6

⇒ c+2 = 8

⇒ d = 8

Therefore, the required two numbers are 6 and 8.

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