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a spherical ball is measured to have a radius of 6 c mwith a possible measurement error of plus-or-minus 0.1 rm c m. use the differentials to estimate the percentage error in computing the volume of the ball.

Sagot :

Percentage error in computing volume is 10%;

r = 6 cm;

Possible measurement error , dr = ±0.1;

dr = 0.1-(0.1) = 0.2 cm;

Volume, V = 4/3 πr³ -(1)

Differentiate w.r.t. r;

dV/dr = 4πr²;  -(2)

Divide (2) by (1);

dV/V = 3 (dr/r)

Put value of r = 6 cm, dr = 0.2 cm;

dV/V = 0.1

Percentage error in computing volume = dV/V × 100% = 10%

volume is a measure of occupied three-dimensional space. it's miles frequently quantified numerically using SI derived units (consisting of the cubic meter and liter) or by way of diverse imperial devices (inclusive of the gallon, quart, cubic inch).

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