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the function must find the substrings of s that start with a vowel and end with a consonant, then print the alphabetically first and alphabetically last of these substrings.

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azikennamdi

According to the parameters given in the questions above, the alphabetically lowest and highest substrings that start with a vowel and end with a Consonant is given below.

What is the determined substrings described above?

The determined substring is given by the following:

def findSubstrings(s):

   sub_strings_list=[]    #the required substrings list

   vowels=['a','e','i','o','u']    #vowels list

   for i in range(0,len(s)):    

       for j in range(i+1,len(s)+1):

           sub_string=s[i:j]    #slicing the original string into substring

           #checking whether the substring starts with a vowel and ends with a consonant

           if(sub_string[0] in vowels and sub_string[-1] not in vowels):    

               if(sub_string not in sub_strings_list):    #checking if the substring is already in the list

                   sub_strings_list.append(sub_string)    #if all conditions are satisfied adding the substring to the list

   sub_strings_list.sort()    #sorting the list alphabetically

   print(sub_strings_list[0])    #printing the first substring in the list

   print(sub_strings_list[-1])    #printing the last substring in the list

s=input()

findSubstrings(s)

Learn more about substrings:
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Full Question:

Consider a string, s — An alphabetically-ordered sequence Of Of s would be {"a", "ab•, "abc • , "bcu, If the sequence is reduced to only those substrings that start with a vowel and end with a consonant, the result is Cab", •abc"}. The alphabetically first element in this reduced list is •ab", and the alphabetically last element is "abc'. As a reminder:

Vowels: a, e, i, o, and u.

Consonants: b, c, d, f, g, h, i, k, l, m, n, p, q, r, s, t, v, w, x, y, and z.

For a given string, determine the alphabetically lowest and highest substrings that start with a vowel and end with a Consonant.

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