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What is the volume of a solution, in milliliters, that contains 1. 5 g lino3 and has a concentration of 0. 40 m?

Sagot :

The volume of a solution, in milliliters, that contains 1. 5 g lino3 and has a concentration of 0. 40 m will be 54.35 m L.

Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.

Molarity = n / V

where

n = number of moles

V = volume of solution in l

Molar mass of [tex]LiNO_{3}[/tex] = M of Li + M of N + 3 * M of O

                                    = 7 + 14 + (3*16)

                                    = 69 g/ mole

since , M = n / V

           n = m / molar mass of  [tex]LiNO_{3}[/tex]

substituting the value of n

Molarity  = (m / molar mass of  [tex]LiNO_{3}[/tex]  ) / V

V = m / molar mass of  [tex]LiNO_{3}[/tex]  * Molarity

   = 1.5 / 69 * 0.40

   = 54.35 mL

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