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How many moles of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)2?

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Eduard22sly

The number of mole of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)₂ is 0.000004 mole

What is molarity?

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

With the above formula, we can determine the number of mole present in the solution. Detail below:

How to determine the mole of the solute in the solution

  • Volume of solution = 1 mL = 1 / 1000 = 0.001 L
  • Molarity of solution = 0.004 M
  • Mole of solute =?

Molarity = mole / Volume

Cross multiply

Mole = Molarity × volume

Mole of solute = 0.004 × 0.001

Mole of solute = 0.000004 mole

Thus, the mole of the solute in the solution is 0.000004 mole

Learn more about molarity:

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