stephaniechavez313
Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

**please look at attached photo for proper understanding* Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a magnitude of 295 N/C.


What is the magnitude of the acceleration of the electron (in m/s2)?

_____m/s2


The electron is initially at rest. What is its speed (in m/s) after 8.50 ✕ 10−9 s?

________m/s

Please Look At Attached Photo For Proper Understanding Inside A Cathode Ray Tube An Electron Is In The Presence Of A Uniform Electric Field With A Magnitude Of class=

Sagot :

onyebuchinnaji

The magnitude of the acceleration of the electron is 5.187 x 10¹³ m/s².

The speed of the electron at the given time is 4.41 x 10⁵ m/s.

Acceleration of the electron

The magnitude of the acceleration of the electron is calculated as follows;

Force on the electron, F = ma = Eq

ma = Eq

a = Eq/m

where;

  • E is electric field
  • q is charge of electron
  • m is mass of electron

a = (295 x 1.6 x 10⁻¹⁹) / (9.1 x 10⁻³¹)

a = 5.187 x 10¹³ m/s²

Speed of the electron

The speed of the electron at the given time is calculated as follows;

v = at

v = ( 5.187 x 10¹³)(8.5 x 10⁻⁹)

v = 4.41 x 10⁵ m/s

Thus, the magnitude of the acceleration of the electron is 5.187 x 10¹³ m/s².

The speed of the electron at the given time is 4.41 x 10⁵ m/s.

Learn more about acceleration here: https://brainly.com/question/605631

#SPJ1

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.