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How many moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride?

Sagot :

299.7 moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride.

Calculation,

The production of aluminium metal is given as,

[tex]Al^{+3} + 3e^{-}[/tex]→ [tex]Al[/tex]

The 3 moles of electrons require to produce 1 gm of atom of aluminium ( weight = 27 ) solution fluoride.

The number of moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride = 3mol×99.9g/1g

The number of moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride = 299.7 moles

To learn about more aluminum fluoride

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