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Sagot :
A 60-m long wire is coiled so that it makes a coil containing 140 square loops, one on top of each other. if the wire carries a current of 21 a, the magnetic dipole moment of the coil will be 0.24 Am2
Dipole moment = i * A
Area = ?
given total length of the wire = 60 m number of square loops = 140total length of the wire = n * ( circumference of one loop) circumference of one loop = total length of the wire / n = 60 / 140 = 0.429 m circumference of one loop = 4 * (side of the square ) 0.429 = 4 * a a = [tex]0.107 m[/tex]
Area of loop = [tex]a^{2}[/tex]= [tex](0.107)^{2}[/tex] = [tex]0.01145 m^{2}[/tex]
Dipole moment = i * A = 21 * 0.01145 = 0.24 A [tex]m^{2}[/tex]
To learn more about Dipole moment here
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