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A circle with center O. Two tangents to the circle from the point C meet the circle at points A, and B. Two lines O B, and O C forms an exterior angle of 250 degrees. Two lines B D, and A D are drawn from a point D on the circle.
In this figure, m∠BDA =
° and m∠BCA =
°.

Sagot :

Lanuel

Based on the calculations, the measure of m∠BDA and m∠BCA are 55° and 70° respectively.

What is a tangent?

In geometry, a tangent is also referred to as a tangent line and it can be defined as a straight line that touches a plane curve at a specific point.

What is a circle?

A circle can be defined as a closed, two-dimensional curved geometric shape with no edges or corners. Also, a circle simply refers to the set of all points in a plane that are located at a fixed distance (radius) from a fixed point (central axis).

First of all, we would determine angle BOA:

∠BOA + ∠BOA = 360° (Angles at a point)

∠BOA + 250° = 360°

∠BOA = 360° - 250°

∠BOA = 110°

Next, we would determine angle BDA:

2 × m∠BDA = ∠BOA (Angle inscribed at the center is twice the angle at the circumference)

2 × m∠BDA = 110°

m∠BDA = 110°/2

m∠BDA = 55°.

What is the theorem of intersecting secants?

The theorem of intersecting secants states that when two (2) lines intersect outside a circle, the measure of the angle formed by these lines is equal to one-half (½) of the difference of the two (2) arcs it intercepts.

By applying the theorem of intersecting secants, angle BCA will be given by this formula:

m∠BCA = ½ × (m<AO - m<BO)

Substituting the given parameters into the formula, we have;

m∠BCA = ½ × (250 - 110)

m∠BCA = ½ × 140

m∠BCA = 70°.

Read more on intersecting secants here: https://brainly.com/question/1626547

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View image Lanuel
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