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A 1. 477 g sample of khp required 30. 27 ml of naoh solution to reach endpoint. Calculate the molarity of the NaOH.

Sagot :

The molarity of the NaOH is  0.238 M when  1. 477 g sample of KHP required 30. 27 ml of NaOH solution to reach endpoint.

Calculation ,

Mass of  KHP  = 1. 477 g

Number of moles of  KHP = given mass / molar mass of  KHP

Number of moles of  KHP = 1. 477 g × 1 mol / 204.23 g  KHP = 0.007 mol

Since , one mole  KHP  requires one mole of NaOH .

Number of moles of NaOH required by 0.007 mol of KHP = 0.007 mol

Molarity of NaOH  = number of moles / volume in lit = 0.007mol/0.03027ml =  0.238 M

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