Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
A string with mass density equal to 0. 0025 kg/m is fixed at both ends and at a tension of 290 n. Resonant frequencies are found at 558 Hz and the next one at 744 Hz. The length of the wire will be L = 0.91 m
A resonant frequency of a string is its natural frequency of a standing wave that is produced in it. The standing waves in the string are called harmonics. A string of a fixed length can have many standing waves. The frequencies of these standing waves are called resonant frequencies.
frequency = 1 / 2L ([tex]\sqrt{\frac{T}{mu} }[/tex])
L = length of the spring
T = Tension
fundamental frequency = 744 - 558 = 186 Hz
186 = 1/2(L) ([tex]\sqrt{\frac{290}{0. 0025 } }[/tex])
L = 340 / (186 * 2)
L = 0.91 m
To learn more about resonant frequency here
https://brainly.com/question/13191113
#SPJ4
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.