Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

24. 00 ml of a 0. 25 m naoh solution is titrated with 0. 10m hcl. What is the ph of the solution after 24. 00 ml of the hcl has been added?.

Sagot :

Tutorconsortium330

The pH of the solution is 12.88.

Calculation:

millimoles of NaOH = volume x Molarity

                                 = 24.00 mL x 0.25 M

                                 = 6.00 mmole

millimoles of HCl = 24.00 mL x 0.10 M

                            = 2.40 mmole

Total volume = 48.00 mL

                           

                            NaOH + HCl   →     NaCl + H2O

initial                       6.00      0               0         0

added                                 2.40

change                   -2.40  -2.40      +2.40  +2.40

equilibrium               3.60    0           2.40    2.40

The pH is determined by the excess of NaOH present.

[NaOH] = millimoles/volume

            = 3.60/48.00

            = 0.075 M

pOH = -log (OH⁻).

        = -log (0.075)

        = 1.12

Then

pH + pOH = pKw = 14.00.

pH = 14 - pOH

pH = 14 - 1.12

pH = 12.88

Learn more about calculation of pH here:

https://brainly.com/question/9408394

#SPJ4

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.