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Sagot :
The probability of 11 voters out of 15 voting candidate A is 0.9770
According to the statement
we have given that the percentage of voters is 81% and poll conducts are 15 and we have to find the probability that 11 of the 15 voters will prefer Candidate
So, For this purpose,
the question in based on binomial probability which means the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes p and q and p+q=1
let probability of choosing candidate A be p
and probability of choosing candidate B be q
In question p=0.81 and q=0.16
n be total number of voters=15
x be number of successes
then P(x=x)= [tex]\frac{n}{x} p^{x} q^{n-x}[/tex]
P(x=11)= [tex]\frac{11}{15} 0.81^{11} 0.16^{4}[/tex]
= 0.9770
So, the probability of 11 voters out of 15 voting candidate A is 0.9770
Learn more about binomial probability here
https://brainly.com/question/15246027
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