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What is Ką for H3PO4(aq) = H(aq) + H₂PO4 (aq)?
OA. K₂ [H₂PO4][H*][H₂PO4]
=
OB. K₂ =
O C. K₂ =
O D. Ka
=
[H₂PO4]
[H*][H₂PO4]
[H*][H₂PO4]
[H₂PO4]
[H3PO4]
[H+][H₂PO4]

What Is Ką For H3PO4aq Haq HPO4 Aq OA K HPO4HHPO4 OB K O C K O D Ka HPO4 HHPO4 HHPO4 HPO4 H3PO4 HHPO4 class=

Sagot :

CrystalQueen

Answer:

C.) [tex]K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}[/tex]

Explanation:

The general structure for a Ka expression is:

[tex]K_a = \frac{[H^+][A^-]}{[HA]}[/tex]

In this expression,

-----> Ka = equilibrium constant

-----> [A⁻] = base

-----> [HA] = acid

The products are in the numerator and the reactants are in the denominator. In this case, H₃PO₄ serves as an acid and H₂PO₄⁻ serves as a base.

As such, the equilibrium expression is:

[tex]K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}[/tex]

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