Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Find the first three harmonics of a string of linear mass density 2. 00 g/m and length 0. 600 m when the tension in it is 50. 0 n.

Sagot :

The first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.

Velocity of the wave

The velocity of the wave is calculated as follows;

v = √T/μ

where;

  • T is tension
  • μ is mass per unit length = 2 g/m = 0.002 kg/m

v = √(50/0.002)

v = 158.1 m/s

First harmonic or fundamental frequency of the wave

f₀ = v/λ

where;

  • λ is the wavelength = 2L

f₀ = v/2L

f₀ = 158.1/(2 x 0.6)

f₀ = 131.8 Hz

Second harmonic of the wave

f₁ = 2f₀

f₁ = 2(131.8 Hz)

f₁ = 263.6 Hz

Third harmonic of the wave

f₂ = 3f₀

f₂ = 3(131.8 Hz)

f₂ = 395.4 Hz

Thus, the first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.

Learn more about harmonics here: https://brainly.com/question/4290297

#SPJ1