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Sagot :
A 45. 0 L gas cylinder contains 988 g He at 23 °C then pressure inside the cylinder is 134.67 atm.
Calculation,
Formula used :The ideal gas equation is given as,
PV = nRT ....(i)
Where , P is pressure of the gas = ?
V = volume of the gas = 45. 0 L
R = universal gas constant = 0. 08206 L⋅atm/mol⋅K
T = Temperature = 23 °C = 23 + 273 = 299 K
n = number of moles = given mass/ molar mass = 988 g/4 = 247 moles
Putting the value of P , V , T , R and n in equation (i) we get
P×45. 0 L = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K
P = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K /45. 0 L = 134.67 atm
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